LARGEST VALUE WITH ALL DIGITS 0-5

Consider a non-empty string array inarr whose elements contain only digits from 0 to 5 such that no element in inarr will contain all the digits from 0 to 5. Identify and print outstr using the logic given below:

  • Identify the non-consecutive unique pairs of elements of inarr, starting from left-most element, such that all the digits from 0 to 5 are present at least once in the pair of elements.
  • Form strings for each pair identified by concatenating the elements of the pair such that the order of their occurrence in inarr is preserved.
  • Set outstr with the largest string formed in the above step. If more than one string exists as largest strings, set outstr with the string whose first or second element used for concatenation appear first in inarr when traversing from left to right.
  • Largest string is a string with maximum number of characters If no such pair is identified, print -1

Input Format

Read inarr with the elements separated by ''(comma) from the standard input stream

Constraints

Read the input

Output Format

Print outstr or -1 accordingly to the standard output stream

Sample Input 0

30012,250232, 53201,3004355,124111

Sample Output 0

300123004355


import java.awt.*;
import java.lang.reflect.Array;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Scanner;
public class ZeroToFive {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String[] innArr = sc.nextLine().split(",");

        ArrayList<String> pairsList = new ArrayList<String>();

        for (int i = 0; i < innArr.length-1; i++) {
            for (int j = i+1; j < innArr.length ; j++) {
                if(j!= i-1 && j!= i+1){
                    String tempPair = innArr[i].trim()+innArr[j].trim();
                    String zeroToFive = "012345";
                    int count = 0;

                    for (int k = 0; k < zeroToFive.length(); k++) {
                        if (tempPair.contains(zeroToFive.charAt(k)+"")){
                            count++;
                        }
                    }

                    if(count == 6) {
                        pairsList.add(tempPair);
                    }
                }
            }
        }
        if(pairsList.isEmpty()){
            System.out.println("-1");
            System.exit(0);
        }

        // Getting lengths of each string into a new list
        Integer[] lenArray = new Integer[pairsList.size()];

        for (int i = 0; i < lenArray.length; i++) {
            lenArray[i] = pairsList.get(i).length();
        }

        int maxLength = Collections.max(Arrays.asList(lenArray));

        ArrayList<String> maxLenPairs = new ArrayList<String>();

        for (int i = 0; i < lenArray.length; i++) {
            if (lenArray[i] == maxLength){
                maxLenPairs.add(pairsList.get(i));
            }
        }
        if(maxLenPairs.isEmpty()){
            System.out.println("-1");
        }else {
            System.out.println(maxLenPairs.get(0));
        }
    }} 

Comments

Post a Comment

Popular posts from this blog

Hackerrank - Quicksort 2 - Sorting

Image
     Problem Submissions Leaderboard Discussions In the previous challenge, you wrote a partition method to split an array into two sub-arrays, one containing smaller elements and one containing larger elements than a given number. This means you 'sorted' half the array with respect to the other half. Can you repeatedly use partition to sort an entire array? Guideline In Insertion Sort, you simply went through each element in order and inserted it into a sorted sub-array. In this challenge, you cannot focus on one element at a time, but instead must deal with whole sub-arrays, with a strategy known as "divide and conquer". When partition is called on an array, two parts of the array get 'sorted' with respect to each other. If partition is then called on each sub-array, the array will now be split into four parts. This process can be repeated until the sub-arrays are small. Notice that when partition is called on just one of the numbers, the...
Read more

Hackerrank - Day of the Programmer

  Marie invented a   Time Machine   and wants to test it by time-traveling to visit Russia on the   Day of the Programmer   (the 256th day of the year) during a year in the inclusive range from 1700 to 2700. From 1700 to 1917, Russia's official calendar was the  Julian calendar ; since 1919 they used the  Gregorian calendar  system. The transition from the Julian to Gregorian calendar system occurred in 1918, when the next day after January 31st was February 14th. This means that in 1918, February 14th was the 32nd day of the year in Russia. In both calendar systems, February is the only month with a variable amount of days; it has 29 days during a  leap year , and 28 days during all other years. In the Julian calendar, leap years are divisible by 4; in the Gregorian calendar, leap years are either of the following: Divisible by 400. Divisible by 4 and  not  divisible by 100. Given a year,  , find the date of the 256th day of t...
Read more

Hackerrank - UNIQUE ARMSTRONG NUMBER

Consider a non-empty array Inarr of unique elements such as satisfies the following condition 0 Starting from the leftmost element in inarr, for each element Form all possible numbers by concatenating pair of elements in inarr such that the second element of the pair appears after the first element in inarr. From the numbers formed, find and add the unique Armstrong numbers) outarr in the order of occurrence of elements in inarr. If two pairs have the same first number, then consider the order of occurrence of second elements in the pairs An Armstrong number is equal the sum of its own digits each raised to the power of the number of digits in the number If there is no Armstrong number found, print-1 as output Input Format First line contains inarr, with the elements separated by ‘,’ (comma) Constraints Read the inputs from the standard input stream Output Format Print outarr, with the elements separated by ',' (comma) to the standard output stream Sample Input 0 15,3,1,70,53,7...
Read more